Chemistry · chapter PYQs
Classification of Elements and Periodicity in Properties, on the exam screen.
6 questions from NEET 2026, Re-NEET 2026, NEET 2020, 6 minutes, marked +4 / −1. See them with solutions.
Classification of Elements and Periodicity in Properties · PYQs
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Q1/6
The correct order of increasing metallic character of Na, Be, P, Mg and Si is:
Answer and explanation
Answer: (1)
Metallic character decreases across a period (left to right) and increases down a group, and it is inversely related to electronegativity. Using Pauling electronegativities (Na 0.9 < Mg 1.2 < Be 1.5 < Si 1.8 < P 2.1), metallic character increases in the reverse order: P < Si < Be < Mg < Na.
Identify the incorrect statement from the following:
Answer and explanation
Answer: (1)
Cationic size decreases with increasing positive charge and across a period, so among Mg, , Al and the largest species is neutral Mg and the smallest is , not Al and ; hence statement (1) is incorrect and is the answer. The others are correct: element 107 is Unnilseptium, Li and Mg show a diagonal relationship, and Al in the given complex has oxidation state +3 with covalency 6.
Among the following options, the correct trend in the electron gain enthalpy is
Answer and explanation
Answer: (3)
Chlorine, not fluorine, releases the most energy on gaining an electron. The 2p subshell of fluorine is so compact that the incoming electron meets strong inter-electronic repulsion, which offsets the favourable nuclear attraction; chlorine's larger 3p shell has no such penalty. Down the rest of the group the value falls with increasing size, giving Cl > F > Br > I. NCERT Class 11, Classification of Elements and Periodicity in Properties.
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion (A): The first ionization enthalpy of O is lower than that of N and F.
Reason (R): The loss of an electron from O leads to stable half-filled p orbital
In light of the above statements, choose the most appropriate answer from the options given below:Answer and explanation
Answer: (1)
Oxygen is ; the fourth 2p electron must pair up in an already-occupied orbital and suffers extra repulsion, so it is comparatively easy to remove. Losing it gives with the half-filled configuration, which is extra stable through exchange energy. That is precisely why oxygen's first ionization enthalpy dips below nitrogen's despite nitrogen having a smaller nuclear charge, and stays below fluorine's. R therefore explains A. NCERT Class 11, Classification of Elements and Periodicity in Properties.
Identify the incorrect match.
List I
List II
P) Unnilunium
I) Mendelevium
Q) Unniltrium
II) Lawrencium
R) Unnilhexium
III) Seaborgium
S) Unununnium
IV) Darmstadtium
Answer and explanation
Answer: (3)
Unnilunium, unniltrium and unnilhexium correctly correspond to elements 101, 103 and 106. The printed 'Unununnium' denotes element 111, whose official name is roentgenium, not darmstadtium; therefore S-IV is the incorrect match. Chapter: Classification of Elements and Periodicity in Properties.
Match each oxide with its nature and select the correct option.
List I
List II
P) CO
I) Basic
Q) BaO
II) Neutral
R) AlO
III) Acidic
S) ClO
IV) Amphoteric
Answer and explanation
Answer: (1)
CO is neutral, BaO basic, AlO amphoteric and ClO acidic. Thus P-II, Q-I, R-IV, S-III. Chapter: Classification of Elements and Periodicity in Properties.
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