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12 real questions from the NEET 2026 paper, in the interface the 2027 exam moves to: one question at a time, a palette, a countdown, +4 / −1. No login, nothing to install.

NEET Mini Mock · 2026 PYQs

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  1. Question 1 · Physics · NEET 2026 · +4 / −1

    The angular speed of a flywheel is increased from 600 rpm to 1200 rpm in 10 s. The number of revolutions completed by the flywheel during this time is:
    Answer and explanation

    Answer: C · System of Particles and Rotational Motion

    With uniform angular acceleration the number of revolutions equals the average angular speed times the time: 600+12002=900\frac{600+1200}{2} = 900 rpm over 1060\frac{10}{60} min = 16\frac{1}{6} min, giving 900×16=150900 \times \frac{1}{6} = 150 revolutions, option (3). Equivalently, using ω22=ω12+2αθ\omega_2^2 = \omega_1^2 + 2\alpha\theta gives θ=300π\theta = 300\pi rad, so θ/2π=150\theta/2\pi = 150.

  2. Question 2 · Physics · NEET 2026 · +4 / −1

    A submarine is designed to withstand an absolute pressure of 100 atm100\ \text{atm}. How deep can it go below the water surface? (Consider the density of water =1000 kg m−3= 1000\ \text{kg m}^{-3}, 1 atm=1×105 Pa1\ \text{atm} = 1 \times 10^{5}\ \text{Pa} and gravitational acceleration g=10 m/s2g = 10\ \text{m/s}^2)
    Answer and explanation

    Answer: A · Mechanical Properties of Fluids

    Absolute pressure at depth hh is P=P0+ρghP = P_0 + \rho g h. So 100×105=1×105+1000×10×h100\times10^{5} = 1\times10^{5} + 1000\times10\times h, giving 99×105=104 h99\times10^{5} = 10^{4}\,h, hence h=990 mh = 990\ \text{m}. Why the other options are wrong: - (B) Off by a factor of 10 in ρg\rho g. - (C) Off by a factor of 10 the other way. - (D) Ignores subtracting P0P_0, using 100×105=ρgh100\times10^5 = \rho g h incorrectly and rounding.

  3. Question 3 · Physics · NEET 2026 · +4 / −1

    Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum LL, notes down the data of time taken to complete 30 oscillations as 60 s and hence calculates the length of the simple pendulum as: (Take π2=9.8\pi^2 = 9.8, and g=9.8g = 9.8 m/s2^2)
    Answer and explanation

    Answer: D · Oscillations

    The time period is T=60/30=2T = 60/30 = 2 s. From T=2πL/gT = 2\pi\sqrt{L/g}, the length is L=gT24π2=9.8×44×9.8=1L = \frac{gT^2}{4\pi^2} = \frac{9.8\times4}{4\times9.8} = 1 m. The other options result from arithmetic or period errors. Why the other options are wrong: - (A) Arithmetic error in L. - (B) Wrong period or factor. - (C) Uses T incorrectly.

  4. Question 4 · Physics · NEET 2026 · +4 / −1

    For a metal of work function 6.6 eV6.6\ \text{eV}, which of the following wavelengths of incident radiation does not give rise to the photoelectric effect? (Take Planck's constant as 6.6×10−34 J s6.6 \times 10^{-34}\ \text{J s})
    Answer and explanation

    Answer: C · Dual Nature of Radiation and Matter

    Photoemission requires photon energy hcλ≥W0\dfrac{hc}{\lambda} \geq W_0, i.e. wavelength λ≤hcW0\lambda \leq \dfrac{hc}{W_0}. Here hcW0=6.6×10−34×3×1086.6×1.6×10−19≈187.5 nm\dfrac{hc}{W_0} = \dfrac{6.6\times10^{-34}\times3\times10^{8}}{6.6\times1.6\times10^{-19}} \approx 187.5\ \text{nm}. Any wavelength longer than this cannot eject electrons; 200 nm>187.5 nm200\ \text{nm} > 187.5\ \text{nm}, so it produces no photoelectric effect. Why the other options are wrong: - (A) 100 nm < 187.5 nm, so it does cause emission. - (B) 150 nm < 187.5 nm, so it does cause emission. - (D) 50 nm < 187.5 nm, so it does cause emission.

  5. Question 5 · Chemistry · NEET 2026 · +4 / −1

    The number of hydrogen atoms present in 5.4 g of urea is: (Given: Molar mass of urea = 60 g mol−160\ \text{g mol}^{-1}; NA=6.022×1023 particles mol−1N_A = 6.022 \times 10^{23}\ \text{particles mol}^{-1})
    Answer and explanation

    Answer: D · Some Basic Concepts of Chemistry

    Moles of urea = 5.4/60 = 0.09 mol. Urea, NH2CONH2NH_{2}CONH_{2}, contains 4 hydrogen atoms per molecule. So number of H atoms = 0.09 * 4 * 6.022 * 102310^{23} ≈\approx 2.168 * 102310^{23}. The distractors arise from using the wrong number of H atoms per molecule or a wrong power of ten. Why the other options are wrong: - (A) Wrong: uses 2 H atoms per molecule. - (B) Wrong: wrong power of ten. - (C) Wrong: wrong power of ten with 2 H atoms.

  6. Question 6 · Chemistry · NEET 2026 · +4 / −1

    Identify the incorrect statement from the following:
    Answer and explanation

    Answer: D · p-Block Elements (Groups 15-18)

    Both nitrogen and oxygen are period-2 elements lacking accessible d-orbitals, so nitrogen cannot form a dπ\pi-pπ\pi bond with oxygen, making statement D incorrect. Nitrogen does form pπ\pi-pπ\pi multiple bonds (as in N2), the heavier elements P and As have vacant d-orbitals allowing dπ\pi-dπ\pi overlap with transition metals, and P, As, Sb show catenation, so those statements are correct. Why the other options are wrong: - (A) Correct statement: N forms pπ\pi-pπ\pi bonds with itself. - (B) Correct statement: P and As use vacant d-orbitals for dπ\pi-dπ\pi bonding. - (C) Correct statement: P, As, Sb show catenation.

  7. Question 7 · Chemistry · NEET 2026 · +4 / −1

    The correct statement with regard to the secondary structure of DNA/RNA is
    Answer and explanation

    Answer: B · Biomolecules

    DNA has a double-stranded helical secondary structure (two antiparallel polynucleotide chains) and its four bases are adenine, guanine, cytosine and thymine. RNA is generally single-stranded and contains uracil in place of thymine, so only the DNA statement pairing double-strand + thymine is correct. Why the other options are wrong: - (A) RNA is single-stranded but contains uracil, not thymine. - (C) RNA is single-stranded, not double-stranded. - (D) DNA is double-stranded and contains thymine, not uracil.

  8. Question 8 · Chemistry · NEET 2026 · +4 / −1

    A solution of copper sulphate is electrolysed for 10 minutes with a current of 1.5 amperes. The mass of copper deposited at cathode is: (Given: Molar mass of Cu = 63 g mol−^{-}1^{1}; 1 F = 96487 C mol−^{-}1^{1})
    Answer and explanation

    Answer: B · Electrochemistry

    Charge passed Q=i t=1.5×(10×60)=900Q = i\,t = 1.5 \times (10\times 60) = 900 C. Deposition follows Cu2++2e−→CuCu^{2+} + 2e^- \rightarrow Cu, so mass =E i tF=63×1.5×6002×96487≈0.294= \frac{E\,i\,t}{F} = \frac{63 \times 1.5 \times 600}{2 \times 96487} \approx 0.294 g, i.e. 0.2938 g. The other values arise from using the wrong n-factor or the wrong time.

  9. Question 9 · Biology · NEET 2026 · +4 / −1

    The sixth mutant codon of beta globin gene causing polymerization of Haemoglobin and change in RBC shape is ______.
    Answer and explanation

    Answer: A · Principles of Inheritance and Variation

    In sickle cell anaemia the sixth codon of the β\beta-globin gene changes from GAG to GUG, so glutamic acid is replaced by valine. This substitution makes haemoglobin polymerize at low oxygen tension and distorts the RBC into a sickle shape, so the mutant codon is GUG.

  10. Question 10 · Biology · NEET 2026 · +4 / −1

    The JGA (Juxta Glomerular Apparatus) is a special sensitive region formed by cellular modifications in _______ related to the same nephron.
    Answer and explanation

    Answer: D · Excretory Products and their Elimination

    The juxtaglomerular apparatus forms at the point of contact where the distal convoluted tubule (macula densa) touches the afferent arteriole (juxtaglomerular cells) of the same nephron. Therefore the correct pairing is distal convoluted tubule and afferent renal arteriole, option 4.

  11. Question 11 · Biology · NEET 2026 · +4 / −1

    Which one of the following is an appropriate example of sexual deceit?
    Answer and explanation

    Answer: B · Organisms and Populations

    In sexual deceit the Mediterranean orchid Ophrys mimics a female bumblebee so that the male bee attempts pseudocopulation and inadvertently pollinates the flower. Female wasp and fig is mutualism, sea anemone and clown fish is commensalism, and cuckoo and crow is brood parasitism, so only Ophrys and bumblebee is sexual deceit.

  12. Question 12 · Biology · NEET 2026 · +4 / −1

    Which one of the following is the site for active ribosomal RNA synthesis?
    Answer and explanation

    Answer: C · Cell: The Unit of Life

    The nucleolus is a non-membrane-bound region within the nucleus and is the site of active ribosomal RNA (rRNA) synthesis and assembly of ribosomal subunits. The centrosome organises spindle fibres, chromatin is the DNA-protein complex carrying genes, and the kinetochore is the protein plate on the centromere for spindle-fibre attachment. Why the other options are wrong: - (A) The centrosome forms spindle fibres during division. - (B) Chromatin carries genetic material but is not the rRNA synthesis site. - (D) The kinetochore anchors spindle fibres at the centromere.

Why practise on this screen

NEET is computer based from 2027. The knowledge transfers from paper practice; the habits do not: clicking instead of shading, a palette instead of page-flicking, a countdown you can always see. What actually changes in the CBT switch covers the details, and reading on a screen is the skill under all of it.

Questions

Is this NEET mock test free?

Yes. No login, no signup, no card. The full BrainIt app is also free until the 2027 exam.

Are these real NEET questions?

Yes. All 12 are from the NEET 2026 NTA paper, graded with the official marking scheme: +4 for a correct answer, -1 for a wrong one, 0 for a skip.

Is NEET 2027 a computer-based test?

Yes. NEET moves from pen-and-paper OMR to CBT from 2027, announced on 15 May 2026 and confirmed by NTA. Practising on a screen with a palette and a countdown is what this page is for.

How many questions and how much time?

12 questions in 12 minutes: one minute per question, the same pace as the real exam's 180 questions in 180 minutes.