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Electric Charges and Fields: NEET previous year questions

Every Electric Charges and Fields question from the official NEET papers on this site, with the answer and a worked solution.

The questions come from Re-NEET 2026 and NEET 2020. Each shows its answer and solution when you open it, so you can attempt it first. For what the chapter covers and how NEET tests it, see the Electric Charges and Fields guide.

Practise on the CBT screen2 questions, 2 minutes, marked +4 / −1Download PDF3 pages, 0.7 MB, with answers and solutions

Re-NEET 2026 · the full paper

  1. Re-NEET 2026 · Q33

    A point charge QQ is placed inside a cavity within a solid isolated conducting sphere. Consider points AA, BB and CC as shown in the figure, where the magnitudes of the electric fields are EAE_A, EBE_B, ECE_C, respectively. The points BB and CC are at the same distance from the center of the solid sphere. The correct option is :

    figure
    1. (1)

      EA=0, EB=ECE_A = 0,\ E_B = E_C

    2. (2)

      EA≠0, EB=ECE_A \neq 0,\ E_B = E_C

    3. (3)

      EA=0, EB>ECE_A = 0,\ E_B > E_C

    4. (4)

      EA≠0, EB<ECE_A \neq 0,\ E_B < E_C

    Answer and solution

    Answer: (2)

    Point AA lies in the empty cavity, not in the conducting material, so the field of QQ is fully present there and EA≠0E_A \neq 0. The induced −Q-Q on the cavity wall and +Q+Q on the outer surface arrange themselves so that the outer surface charge is UNIFORM regardless of where the cavity sits, so outside the sphere the field is exactly that of a point charge QQ at the centre. Since BB and CC are equidistant from that centre, EB=ECE_B = E_C. NCERT Class 12, Electric Charges and Fields (electrostatics of conductors).

    Why the other options are wrong:

    - (1) confuses the cavity with the conducting material - the field vanishes inside the METAL, not inside the hollow
    - (3) combines the cavity error with the idea that the off-centre cavity biases the external field towards BB
    - (4) correctly sees EA≠0E_A \neq 0 but wrongly assumes the external field is skewed away from the cavity side

NEET 2020 · the full paper

  1. NEET 2020 · Q170

    A spherical conductor of radius 10 cm has a charge of 3.2 × 10⁻⁷ C distributed uniformly. What is the magnitude of electric field at a point 15 cm from the centre of the sphere? (1/(4πε₀) = 9 × 10⁹ N m² C⁻²)

    1. (1)

      1.28×1051.28 \times 10^{5} N C−1^{-1}

    2. (2)

      1.28×1061.28 \times 10^{6} N C−1^{-1}

    3. (3)

      1.28×1071.28 \times 10^{7} N C−1^{-1}

    4. (4)

      1.28×1041.28 \times 10^{4} N C−1^{-1}

    Answer and solution

    Answer: (1)

    The electric field outside a charged spherical conductor is given by E=14πϵ0Qr2E = \frac{1}{4\pi \epsilon_0} \frac{Q}{r^2}. Substituting the values, E=9×109×3.2×10−7(0.15)2=1.28×105 N/CE = 9 \times 10^9 \times \frac{3.2 \times 10^{-7}}{(0.15)^2} = 1.28 \times 10^5\ N/C. Chapter: Electric Charges and Fields.

Practise Electric Charges and Fields in the app: it brings back the questions you get wrong, so the chapter improves, not just your memory of these. Or try the free CBT mock. All chapters: NEET chapter-wise PYQs.

Questions

Are these the official NEET questions on Electric Charges and Fields?

Yes. They are the questions NTA set in each paper, in its wording. The solutions are written by BrainIt.

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