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Chemistry

The d- and f-Block Elements

Transition metals and their trends are the focus: electronic configurations, variable oxidation states, colour, magnetic properties, catalysis, potassium dichromate and permanganate chemistry, and lanthanoid contraction. NEET blends recall on trends and exceptions with one standard numerical, the spin-only magnetic moment.

Exam rules change between cycles. Confirm dates, syllabus and pattern against NTA's official site. We are not NTA.

Weightage: what the paper actually did

The d- and f-Block Elements carried 3 questions in the NEET 2026 paper. One paper is a data point, not a destiny: NTA moves weight between chapters every cycle, which is why the weightage tables deserve care. The stable facts are the paper's shape: 180 questions, 720 marks, +4 right, −1 wrong.

Sample PYQs from this chapter

Real questions NTA asked from The d- and f-Block Elements, with the answer and the working. Try before you peek.

Question 1 · NEET 2026

Although +3 oxidation state is most common in lanthanoids, cerium still shows +4 oxidation state because:
  1. A.After losing one more electron, it acquires 4f144f^{14} electronic configuration.
  2. B.Its nearest inert gas is Radon.
  3. C.Its atomic number is 61.
  4. D.After losing one more electron, it acquires 4f04f^{0} electronic configuration.
Answer and explanation

Answer: D

Cerium (Z = 58) has the configuration [Xe]4f1 5d1 6s2; on going to Ce4+ it loses its outer electrons to reach the especially stable, empty 4f0 (noble-gas-like) configuration, which is why it readily shows the +4 state. The options citing 4f14, radon, or atomic number 61 are factually wrong for cerium. Why the other options are wrong: - (A) Wrong: Ce4+ does not reach 4f14; that stability applies to Yb/Lu region. - (B) Wrong: cerium's nearest inert gas is xenon, and it is irrelevant. - (C) Wrong: cerium's atomic number is 58, not 61.

Question 2 · NEET 2026

The calculated 'spin-only' magnetic moment of Ti2+Ti^{2+} (3d23d^2) is:
  1. A.5.92 BM
  2. B.3.87 BM
  3. C.2.84 BM
  4. D.4.90 BM
Answer and explanation

Answer: C

The spin-only magnetic moment is μ=n(n+2)\mu = \sqrt{n(n+2)} BM, where n is the number of unpaired electrons. Ti2^{2}+^{+} is [Ar]3d2^{2} with 2 unpaired electrons, so μ=2(2+2)=8≈2.84\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.84 BM. Why the other options are wrong: - (A) 5.92 BM corresponds to 5 unpaired electrons. - (B) 3.87 BM corresponds to 3 unpaired electrons. - (D) 4.90 BM corresponds to 4 unpaired electrons.

How to practise The d- and f-Block Elements

Chapter by chapter, against real past-paper questions, on a screen: NEET is computer based from 2027. Read the chapter once, then attempt its PYQs until your accuracy stops climbing, and let the wrong answers tell you which lines to reread. If the chapter keeps refusing to stick, that has its own guide. There is also a free 12-question mock on the exam screen.

Nearby Chemistry chapters

Questions

How many questions did The d- and f-Block Elements have in NEET 2026?

The d- and f-Block Elements carried 3 questions in the NEET 2026 paper. Weightage shifts between cycles, so treat it as a probability, not a promise.

Where can I practise The d- and f-Block Elements PYQs for NEET?

In the BrainIt app, free until the 2027 exam: its bank holds 50,000 past NTA questions tagged to all 83 chapters, including this one, with accuracy tracked per chapter. Sample questions from this chapter are on this page.

Is The d- and f-Block Elements important for NEET 2027?

It is part of the Chemistry syllabus the paper draws from, and NEET 2027 is computer based, so practise it on a screen. Your own accuracy in the chapter matters more than any weightage table: a heavy chapter you already score well on needs less time than a light one you keep missing.

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