Are these the official NEET questions on The d- and f-Block Elements?

Yes. They are the questions NTA set in each paper, in its wording. The solutions are written by BrainIt.

The d- and f-Block Elements NEET PYQs with Solutions (2020 to 2026) PDF

The questions come from NEET 2026, Re-NEET 2026 and NEET 2020. Each shows its answer and solution when you open it, so you can attempt it first. For what the chapter covers and how NEET tests it, see the The d- and f-Block Elements guide.

Practise on the CBT screen7 questions, 7 minutes, marked +4 / −1 Download PDF4 pages, 0.7 MB, with answers and solutions

NEET 2026 · the full paper

NEET 2026 · Q47

Match List I with List II:

List I	List II
P) $\mathrm{V}_{2}\mathrm{O}_{5}$	I) Preparation of ammonia from $\mathrm{N}_{2}$ / $\mathrm{H}_{2}$ mixture
Q) $\mathrm{Fe}$	II) Polymerisation of alkynes
R) $\mathrm{PdCl}_{2}$	III) Preparation of $\mathrm{H}_{2}\mathrm{SO}_{4}$ and $\mathrm{SO}_{2}$
S) Ni complex	IV) Oxidation of ethyne to ethanal

(1)
P-III, Q-IV, R-I, S-II
(2)
P-IV, Q-I, R-III, S-II
(3)
P-II, Q-I, R-IV, S-III
(4)
P-III, Q-I, R-IV, S-II

Answer and solution

Answer: (4)

$\mathrm{V}_{2}\mathrm{O}_{5}$ is the contact-process catalyst linked with $\mathrm{H}_{2}\mathrm{SO}_{4}$ / $\mathrm{SO}_{2}$ chemistry (III); Fe is the Haber-process catalyst for ammonia from $\mathrm{N}_{2}$ / $\mathrm{H}_{2}$ (I); $\mathrm{PdCl}_{2}$ catalyses Wacker oxidation of ethyne/ethene to ethanal (IV); and Ni complexes catalyse polymerisation of alkynes (II). Hence P-III, Q-I, R-IV, S-II.

NEET 2026 · Q66
Although +3 oxidation state is most common in lanthanoids, cerium still shows +4 oxidation state because:
1. (1)
  After losing one more electron, it acquires $4f^{14}$ electronic configuration.
2. (2)
  Its nearest inert gas is Radon.
3. (3)
  Its atomic number is 61.
4. (4)
  After losing one more electron, it acquires $4f^{0}$ electronic configuration.
Answer and solution
Answer: (4)
Cerium (Z = 58) has the configuration [Xe]4f1 5d1 6s2; on going to Ce4+ it loses its outer electrons to reach the especially stable, empty 4f0 (noble-gas-like) configuration, which is why it readily shows the +4 state. The options citing 4f14, radon, or atomic number 61 are factually wrong for cerium.
NEET 2026 · Q80
The calculated 'spin-only' magnetic moment of $Ti^{2+}$ ( $3d^2$ ) is:
1. (1)
  5.92 BM
2. (2)
  3.87 BM
3. (3)
  2.84 BM
4. (4)
  4.90 BM
Answer and solution
Answer: (3)
The spin-only magnetic moment is $\mu = \sqrt{n(n+2)}$ Bohr magneton (BM), where n is the number of unpaired electrons. Ti $^{2+}$ is [Ar]3d $^{2}$ with 2 unpaired electrons, so $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.84$ BM.

Re-NEET 2026 · the full paper

Re-NEET 2026 · Q61
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.

Assertion (A): Generally, 3d transition metals have high melting points.

Reason (R): Involvement of 3d-electrons in addition to 4s-electrons in the interatomic metallic bonding.

In light of the above statements, choose the most appropriate answer from the options given below:
1. (1)
  Both A and R are correct and R is the correct explanation of A
2. (2)
  Both A and R are correct and R is NOT the correct explanation of A
3. (3)
  A is correct but R is not correct.
4. (4)
  A is not correct but R is correct
Answer and solution
Answer: (1)
Melting point tracks the strength of the metallic bond, which depends on how many electrons each atom contributes to the delocalised sea. In s-block metals only the ns electrons participate, but in the 3d series the unpaired 3d electrons join the 4s electrons in bonding, producing much stronger interatomic attraction and correspondingly high melting points. The trend peaks near the middle of the series, where the number of unpaired d electrons is greatest. R is therefore the correct explanation of A. NCERT Class 12, The d- and f-Block Elements.
Re-NEET 2026 · Q67
The lanthanide ion having four unpaired electrons is (Given : Atomic numbers of Ce = 58, Nd = 60, Tb = 65 and Ho = 67)
1. (1)
  $\mathrm{Nd}^{3+}$
2. (2)
  $\mathrm{Ce}^{3+}$
3. (3)
  $\mathrm{Tb}^{3+}$
4. (4)
  $\mathrm{Ho}^{3+}$
Answer and solution
Answer: (4)
Lanthanoid tripositive ions have the configuration $[\mathrm{Xe}]4\mathrm{f}^{\mathrm{n}}$ , where n is the atomic number minus 57. That gives $\mathrm{Ce}^{3+} = 4f^1$ , $\mathrm{Nd}^{3+} = 4f^3$ , $\mathrm{Tb}^{3+} = 4f^8$ and $\mathrm{Ho}^{3+} = 4f^{10}$ . Filling seven f orbitals by Hund's rule, $4f^{10}$ places three pairs and leaves FOUR unpaired electrons, so $\mathrm{Ho}^{3+}$ is the answer. NCERT Class 12, The d- and f-Block Elements (lanthanoids).
Re-NEET 2026 · Q85
The green paramagnetic species formed by heating $\mathrm{KMnO}_{4}$ at 513 K is
1. (1)
  $\mathrm{K}_{2}\mathrm{MnO}_{4}$
2. (2)
  $\mathrm{Mn}_{3}\mathrm{O}_{4}$
3. (3)
  $\mathrm{MnO}$
4. (4)
  $\mathrm{KO}_{2}$
Answer and solution
Answer: (1)
Heating permanganate near 513 K decomposes it as 2KMnO $_{4}$ → K $_{2}$ MnO $_{4}$ + MnO $_{2}$ + O $_{2}$ at 513 K. The manganate ion $\mathrm{MnO}_{4}^{2-}$ has manganese in the +6 state with a $d^1$ configuration, so it is both intensely green and paramagnetic - permanganate itself, with $d^0$ manganese(VII), is purple and diamagnetic. NCERT Class 12, The d- and f-Block Elements (potassium permanganate).

NEET 2020 · the full paper

NEET 2020 · Q111
Identify the incorrect statement.
1. (1)
  Transition metals and their compounds are known for catalytic activity because they can adopt multiple oxidation states and form complexes.
2. (2)
  Interstitial compounds form when small atoms such as H, C or N occupy spaces in metal crystal lattices.
3. (3)
  The oxidation states of chromium in CrO $_{4}^{2-}$ and Cr $_{2}$ O $_{7}^{2-}$ are not the same.
4. (4)
  Cr $^{2+}$ (d $^{4}$ ) is a stronger reducing agent than Fe $^{2+}$ (d $^{6}$ ) in water.
Answer and solution
Answer: (3)
Chromium is +6 in both CrO $_{4}^{2-}$ and Cr $_{2}$ O $_{7}^{2-}$ , so the statement that their oxidation states differ is incorrect. The other three statements are valid. Chapter: The d- and f-Block Elements.

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The d- and f-Block Elements: NEET previous year questions

NEET 2026 · the full paper

Re-NEET 2026 · the full paper

NEET 2020 · the full paper

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