Are these the official NEET questions on Electromagnetic Waves?

Yes. They are the questions NTA set in each paper, in its wording. The solutions are written by BrainIt.

Electromagnetic Waves NEET PYQs with Solutions (2020 to 2026) PDF

The questions come from NEET 2026, Re-NEET 2026 and NEET 2020. Each shows its answer and solution when you open it, so you can attempt it first. For what the chapter covers and how NEET tests it, see the Electromagnetic Waves guide.

Practise on the CBT screen5 questions, 5 minutes, marked +4 / −1 Download PDF4 pages, 0.8 MB, with answers and solutions

NEET 2026 · the full paper

NEET 2026 · Q45

Match List-I (Electromagnetic wave) with List-II (Production) and choose the correct answer from the options given below.

List I	List II
P) Microwave	I) Electrons in atoms emit light when they move from a higher energy level to a lower energy level
Q) Visible light	II) Radioactive decay of nucleus
R) Gamma rays	III) Vibration of atoms and molecules
S) Infra-red rays	IV) Klystron valve or magnetron valve

(1)
P-III, Q-I, R-II, S-IV
(2)
P-III, Q-IV, R-I, S-II
(3)
P-IV, Q-I, R-II, S-III
(4)
P-IV, Q-III, R-II, S-I

Answer and solution

Answer: (3)

Microwaves are generated by klystron or magnetron valves (P-IV). Visible light is emitted when atomic electrons drop from higher to lower energy levels (Q-I). Gamma rays are produced in radioactive decay of the nucleus (R-II). Infra-red radiation arises from the vibration of atoms and molecules (S-III). This matches option (3).

Re-NEET 2026 · the full paper

Re-NEET 2026 · Q38
An electromagnetic wave travelling in a lossless dielectric medium having a dielectric constant, $\varepsilon_r = 9$ , has the electric field, $E_x = E_0\sin(kz - 2\pi \times 10^6 t)\ \text{Vm}^{-1}$ where $E_0$ is the amplitude and $k$ is the wave vector. Among the following options, the incorrect choice is
1. (1)
  The speed of the electromagnetic wave inside the medium is $10^8\ \text{ms}^{-1}$
2. (2)
  The wavelength of the electromagnetic wave inside the medium is 300 m
3. (3)
  The magnetic field is given by the relation $B_y = \frac{B_0}{v}\sin(kz - 2\pi \times 10^6 t)$ where $v$ is the speed of the electromagnetic wave inside the medium
4. (4)
  The direction of propagation of the electromagnetic wave is along $+z$
Answer and solution
Answer: (2) or (3) NTA accepted more than one option.
NTA accepted both option (2) and option (3) as answers. The refractive index is $n = \sqrt{\varepsilon_r} = 3$ , so $v = \frac{c}{n} = 10^8\ \text{m s}^{-1}$ , making option (1) correct. From $\omega = 2\pi \times 10^6$ , the frequency is $10^6\ \text{Hz}$ , hence $\lambda = \frac{v}{f} = 100\ \text{m}$ , not 300 m; therefore option (2) is incorrect. Option (3) is also incorrect as printed: the magnetic field should be $B_y = \frac{E_0}{v}\sin(kz-\omega t)$ , whereas the option uses $B_0/v$ . Option (4) is correct because $kz-\omega t$ represents propagation along $+z$ . NCERT Class 12, Electromagnetic Waves.
Re-NEET 2026 · Q43
The following table presents the part of the electromagnetic spectrum and their corresponding major applications. The correct option is:
List I
List II
P) Microwave
I) For purifying the water
Q) UV rays
II) For warming the food
R) Gamma rays
III) For AM and FM communication systems
S) Radio wave
IV) For treating the Cancer cells
1. (1)
  P-I, Q-II, R-III, S-IV
2. (2)
  P-I, Q-IV, R-II, S-III
3. (3)
  P-II, Q-I, R-IV, S-III
4. (4)
  P-II, Q-IV, R-III, S-I
Answer and solution
Answer: (3)
Microwaves are absorbed by water molecules in food and heat it, so P-II. Ultraviolet radiation is germicidal and is used in water sterilisation, so Q-I. Gamma rays carry enough energy to destroy malignant tissue and are used in radiotherapy, so R-IV. Radio waves are the carriers in amplitude modulated (AM) and frequency modulated (FM) broadcasting, so S-III. NCERT Class 12, Electromagnetic Waves (electromagnetic spectrum).

List I	List II
P) Microwave	I) For purifying the water
Q) UV rays	II) For warming the food
R) Gamma rays	III) For AM and FM communication systems
S) Radio wave	IV) For treating the Cancer cells

NEET 2020 · the full paper

NEET 2020 · Q142
Light with an average flux of 20 W cm $^{-2}$ falls on a non-reflecting surface at normal incidence having surface area 20 cm $^{2}$ . The energy received by the surface during a time span of 1 minute is
1. (1)
  $12 \times 10^{3}$ J
2. (2)
  $24 \times 10^{3}$ J
3. (3)
  $48 \times 10^{3}$ J
4. (4)
  $10 \times 10^{3}$ J
Answer and solution
Answer: (2)
The energy received is given by E = flux × area × time. Substituting, $E = 20\ W/cm^2 \times 20\ cm^2 \times 60\ s = 24 \times 10^3\ J$ . Chapter: Electromagnetic Waves.
NEET 2020 · Q168
The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is (c = speed of electromagnetic waves)
1. (1)
  1 : 1
2. (2)
  1 : c
3. (3)
  1 : c $^{2}$
4. (4)
  c : 1
Answer and solution
Answer: (1)
In an electromagnetic wave the electric and magnetic energy densities are equal because E = cB and c $^{2}$ = 1/( $\mu$ $_{0}$ ε $_{0}$ ). Their contributions to intensity are therefore in the ratio 1:1. Chapter: Electromagnetic Waves.

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Electromagnetic Waves: NEET previous year questions

NEET 2026 · the full paper

Re-NEET 2026 · the full paper

NEET 2020 · the full paper

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